re = /^(?P<header>[^:\n]+):\s*(?P<value>.+)/m
str = 'ID: 1
Name: Jon Doe
Address: 123 Main St Anytown, USA
Age: 25'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html