re = /^(?=[a-zA-Z0-9]{1,80}$)[a-zA-Z]+[0-9]*$/m
str = 'a
a1
ab12
aAc
aAd12
ad123456789012345678901234567890123456789012345678901234567890123456789012345678
ad1234567890123456789012345678901234567890123456789012345678901234567890123456782
1
1a
a1111
a3333d'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html