re = /^path(?:(?=\?)(?:[?&]foo=(\d*)(?=[&#]|$)|(?![?&]foo=)[^#\n])+)?(?=#|$)/m
str = 'path
pathbreak
path?foo=123
path?foo=-123
invalid?foo=1
path?foo=123&bar=abc
path?bar=abc&foo=123
path?bar=foo
path#anchor
path#foo=bar
path?foo=123#bar
path?foo=123abc
path?foo'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html