import Foundation
let pattern = #"[\d]+[,|.]?[\d]+[\ ]?[д|с|м|мк|н|п|ф|а|з|и]+[Ф]"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
SMD 0603 49,9 Ом ±1% 0,1 Вт CR0603-FX-49R9ELF
SMD 0603 49,9 Ом ± 1% 0,1Вт CR0603-FX-49R9ELF
SMD 0603 49,9 Ом ±1% 0.1 Вт CR0603-FX-49R9ELF
SMD 0603 49,9 Ом ± 1% 0.1Вт CR0603-FX-49R9ELF
SMD 0603 49,9 Ом ±1% 0.11 Вт CR0603-FX-49R9ELF
SMD 0603 49,9 Ом ± 1% 0.11Вт CR0603-FX-49R9ELF
SMD 0805 100 нФ ± 10 % 50 В X7R 08055C104KAT2A AVX
SMD 0805 100 нФ ±10% 50В X7R 08055C104KAT2A AVX
SMD 0805 100 нФ ± 10 % 50.0 В X7R 08055C104KAT2A AVX
SMD 0805 100 нФ ±10% 50.0В X7R 08055C104KAT2A AVX
50.9В
50.99Вт
50.9 В
50.999 Вт
а50ю
100.00 мкФ
100.00 нФ
100.00 пФ
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression