re = /how to/m
str = '<li><a href="xxx.html" title="xxx">xxx (22)</a></li>
<li><a href="yyy.html" title="yyy">yyy (21)</a></li>
<li><a href="zzz.html" title="zzz">zzz (13)</a></li>
<li><a href="xxx.html" title="xxx">xxx (23)</a></li>
<li><a href="yyy.html" title="yyy">yyy (24)</a></li>
<li><a href="zzz.html" title="zzz">zzz (15)</a></li>
So, this a menu in html. I need to match in order those numbers from the end. Suppose the last line, `<li><a href="ccc.html" title="ccc">ccc (7)</a></li>` instead of (7) I would have (6). The regex formula should match this row.
So, the order of the numbers must be taken into account, and regex formula should match only where the number does not match the default number.'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html