re = /^([12]\d{3}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01]))$/m
str = '2000-10-22
2000-10-2
2000-1-22
2000-14-22
2000-01-01
2000-01-99
2000-00-01
2000-01-00
0001-01-01
// You can show origina post on albertcolom.com/blog'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html