import Foundation
let pattern = #"^((192\.168\.1|201.110\.2(0[8-9]|1\d|2[0-3]))\.([1-9]\d?|1\d\d|2[0-3]\d|24\d|25[0-4]))$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
1.2.3.4
69.69.69.69
192.168.1.0
192.168.1.1
192.168.1.69
192.168.1.233
192.168.1.254
192.168.1.255
201.110.207.1
201.110.208.1
201.110.208.127
201.110.219.123
201.110.223.254
201.110.223.255
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression