import Foundation
let pattern = #"^([\r\n]*[^\r\n]+(?:[\r\n]+[^\r\n]+)*)[\r\n]+$"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
aaaaaaaaaa
11111111111111111111111
2222222222222222222222222222222222222
333333333333333333333333333333333333333
44
55
67
8
9
90
0
-
=-
=
l
j
g
f
d
s
x
cv
b
n
m
j
h
d
d
g
uj
j
j
h
g
f
gt
t
t
t
tt
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #"$1"#
let lookupRange = (testString as NSString).range(of: pattern, options: .regularExpression, range: stringRange)
if lookupRange.intersection(stringRange) != nil {
let result = regex.stringByReplacingMatches(in: testString, range: lookupRange, withTemplate: substitutionString)
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression