# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"\b[0-9]{10}\b"
test_str = ("National Provider Identifier\n"
"Requirements: 10 consecutive digit number\n\n"
"Pattern:\n"
"\\b[0-9]{10}\\b\n\n"
"Test Cases:\n"
"Positive (should fire):\n"
"10 digits consecutively 1234507890\n"
"Embedded in text with spaces NPI: oops 1234507890 there is text here\n\n"
"Negative (should not fire):\n"
"Too many digits 12345078901\n"
"Not consecutive 1234567-890\n\n"
"Embedded in text no spaces oops1234507890there is text here\n\n"
"Phone number formats:\n"
"2028080012 (this one will fire, false positive)\n"
"202-808-0012\n"
"202.808.0012\n"
"202 808 0012 ")
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html