import Foundation
let pattern = #"x(?:(?(1)(?!)|(a))|(?(2)(?!)|(b))|.){0,10}?y(?(1)|(?!))(?(2)|(?!))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
Match:
...x12a456b89y... ...x12a456b89y...
...xaabbaabby...
x...a.y.b...y (there are 11 chars between x and y, no match is correct!)
...x..a...b..y...
...x..b...a..y...
...x..a...b..y...a...
...x..a...b..y...b...
...x..a...b..y...y...
...x..a.x.b..y...
...x..a.y.b..y...
...xaabbaabbay...
...x..a...b..y... ...x..a...b..y... (2 matches)
...xaby...xaby... (2 matches)
Don't match:
...x..a...b......
...x......b..y...
...x..a......y...
...x..a...b......y...
...x......b..y...a...
...x..a......y...b...
...x..a.y.b......
...x..a.y.b......y...
...x..a.y.b.x....y...
.a.x......b..y...
.b.x..a......y...
x...y...a...b
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression