re = /^([0-2]\.\d+\.\d+$)|(3\.0\.\d+$)|(3\.1\.\d$)|(3\.1\.1[1-6]$)/m
str = '
1.1.17
1.999.99
2.0.0
2.1.17
2.999.99
3.1.16
3.1.16
3.0.17
3.1.17'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html