re = /^(?:\+\d{1,3}|\d{2,3})$/m
str = '01
+1
00
99
999
+999
-1
9999
--1
+1+
0
+
-
1
99999
-1234'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html