$re = '/(\d$)/m';
$str = '1, 83, 1, 89, 152, 78, 25.54051, 1, 1, 0, 0, 0, 1, 0, 1, "1/13/97", "1/18/97", "12/31/02", 5, 0, 2178, 0
2, 49, 1, 84, 120, 60, 24.02398, 1, 0, 0, 0, 0, 0, 1, 1, "1/19/97", "1/24/97", "12/31/02", 5, 0, 2172, 0
';
$subst = "\1,";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php