import Foundation
let pattern = #"^(?<type>revert)(?:\((?<scope>[a-z-]+)\))?(?<breaking>!)?: (?:|(?:.+\n\n(?:- )?))(?:(?:(?:(?<owner>[\d*a-z~-][\w*.~-]*)\/(?<repository>[\da-z~-][\w.~-]*))|(?<user>[\da-z~-][\w.~-]*))@)?(?<hash>[\da-z]+)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
revert(release-alpha)!: flex-development/mlly@0f2fb6e2a5a11c6558c48bffa02ae881999cfd8d
revert: flexdevelopment@0f2fb6e2a5a11c6558c48bffa02ae881999cfd8d
revert: 0f2fb6e2a5a11c6558c48bffa02ae881999cfd8d
revert(release): "release: 1.0.0-alpha.2"
- 0f2fb6e2a5a11c6558c48bffa02ae881999cfd8d
revert(release): "release: 1.0.0-alpha.2"
flexdevelopment@0f2fb6e2a5a11c6558c48bffa02ae881999cfd8d
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression