re = /(\/)(0-9)(\/j\/)/mi
str = '<div>... <span class="highlight highlight--wrapping">Chuck</span> <span class="highlight highlight--wrapping">Feeney</span> (David Cantwell for Forbes)
On a cool summer afternoon at Dublin\'s Heuston Station, <span class="highlight highlight--wrapping">Chuck</span> <span class="highlight highlight--wrapping">Feeney</span>, 81...<br> slowly limped out of the station completely unnoticed. And that\'s just how <span class="highlight highlight--wrapping">Feeney</span> likes it.
<span class="highlight highlight--wrapping">Chuck</span> <span class="highlight highlight--wrapping">Feeney</span> is the James ...</div>
https://www.procaretherapy.com/school-jobs/contracted-early-intervention-school-psychologist-job-near-king-of-prussia-pa/1327725/j/#apply'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html