import Foundation
let pattern = ##"""
^ # Start of line
[^()\r\n]* # Any number of non parentheses characters
(?:\([^()\r\n]*(?:\([^()\r\n]*(?:\([^()\r\n]*(?:\([^()\r\n]*\))?[^()\r\n]*\))?[^()\r\n]*\))?[^()]*\))?
[^()\r\n]* # Any number of non parentheses characters
:(?!=) # Colon NOT followed by an equal-sign
[^()\r\n]* # Any number of non parentheses characters
(?:\([^()\r\n]*(?:\([^()\r\n]*(?:\([^()\r\n]*(?:\([^()\r\n]*\))?[^()\r\n]*\))?[^()\r\n]*\))?[^()]*\))?
[^()\r\n]* # Any number of non parentheses characters
$
"""##
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .allowCommentsAndWhitespace])
let testString = #"""
all: whatevs
all:
deps:
$(EXECUTABLE): $(OBJECTS)
$(sort $(a)): $(b) ;
$(a): b
$(a:b=c) : d
$(X:a=b) : w ;
lib/%.o: CFLAGS := -fPIC -g
%.o: CFLAGS := -g
ifneq ($(words $(subst :, ,$(CURDIR))), 1)
hash := $(shell printf '\043')
var := $(shell find . -name "*.c")
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression