re = /^((1?\d{1,2}|2([0-4]\d|5[0-5]))\.){3}(1?\d{1,2}|2([0-4]\d|5[0-5]))$|^$/m
str = '192.168.1.1
192.168.255.255
8.8.8.8
10.10.1.1
021.8.8.8
8.021.021.8
0.0.0.0
1.0.0.0
100.10.1.1
20.200.2.2
255.255.255.254
266.274.255.0
200.249.255.8
0.0.0.0
1.0.0.0
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html