import Foundation
let pattern = #"^[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
ccc7c43c-8f4f-4963-a8f5-b2a7dfc2711a
018b587c851a7c9488eaf59f5c6dc701
6edf08d2-7102-11ee-b962-0242ac120002
6edf08d2-7102-11ee-b9623-0242ac12002
018b587c-851a-7c94-88ea-f59f5c6dc701
018b587c-851a-7c94-88ea-f59f5c6dcx01
218b5876-851a-7c94-uuea-f59f5c6dc701
// You can show origina post on albertcolom.com/blog
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression