re = /^(19[0-9][0-9]|20[012][0-9])$/m
str = '1980
2005
2015
2029
2030
1853
1900
1959
14
2017
2000
2030
2029
1960
1899
2000
1999
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html