re = /^((?&byte))\.((?&byte))\.((?&byte))\.((?&byte))$(?(DEFINE)(?<byte>25[0-5]|2[0-4]\d|[01]?\d\d?))/m
str = '128.0.25.120
255.255.255.255
0.0.0.0
102.10.0i.10'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html