re = /(\d+ +)(AB|DE|RG|DU)/m
str = '23 AB 5400 DE 68 RG
33 DU 88 DE 8723 AB
55 RG 76 AB 92 DE'
subst = '\\1\\2'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html