re = /(?:\d.*){9,}/m
str = '123454576889
12fsdfsdf34343434dfgfg34545
12345678aaaaaaaaaa
12345aaaa6789
(123)567-89-10
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html