re = /(?<! [\d.] )
(?=
\d+ \. \d+
(?! [\d.] )
)
1 \.? 0 \.? 2 \.? 0 \.? 0
(?! [\d.] )
/x
str = '10200
1.0200
10.200
102.00
1020.0
.10200
1.02.00
10200.
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html