import Foundation
let pattern = ##"\[[^][]*](*SKIP)(*F)|(?:https?://)?(?:www\.)?[\w@:%.+~#=]{2,256}\.[a-z]{2,6}\b[\w-@:%+.~#?&/=]*"##
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
www.example.com
http://example.com.nz
example.com
http://www.example.com?2rjl6
example.com/first/second
https://example.us.edi?34535/534534?dfg=g&fg
etc...
I want no match if any of the above URLs are enclosed in square brackets [ ] like this:
[www.example.com]
[http://example.com.nz]
etc...
.aaaa
e.g.
Lorem ipsum dolor sit amet, consectetur [http://example.com.nz] llamcorper et lacus. Morbi sodales convallis lectus a efficitur: example.com/first/second vitae nisl placerat.
Fusce non ipsum a augue http://example.com.nz http://www.example.com?2rjl6 aculis augue. Nullam eu nulla lectus.
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression