re = /\n(?!\d+,)/m
str = 'id, text field1, text field2
1,some text,another text
2,some
1999-06-21 text,another text
3,some text,another text
1a,wewe
'
subst = ' '
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html