re = /(\d)[\s.]+(?=\d)/m
str = 'This is an 8-string 12.34.5678; and this is another 13-string 1234 5678 9123 0 okay?'
subst = '$1'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html