const regex = /^(?!\([^()\n]*\)$|.*([()])[^()\n]*(?=\1)|[^()\n]*[()](?:[^()\n]*[()][^()\n]*[()])*[^()\n]*$|.*\([A-Z]\))\(?[A-Z](?: (?:and|or) \(?[A-Z]\)?)*$/gm;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('^(?!\\([^()\\n]*\\)$|.*([()])[^()\\n]*(?=\\1)|[^()\\n]*[()](?:[^()\\n]*[()][^()\\n]*[()])*[^()\\n]*$|.*\\([A-Z]\\))\\(?[A-Z](?: (?:and|or) \\(?[A-Z]\\)?)*$', 'gm')
const str = `A and B and C and D
(A or B) and C
(A or B or C) and D
(A or B or C or D) and E
A and (B or C) and D
A and (B or C) or (C and D)
A or (B and C)
(A and B) or (C and D)
A
A and (B) and C
A and B)
A and B and C and
(A or B and C
(A or B or C) and D or
(A or B or C or D and E
A and or (B or C) and D
A and (B or (C and D)))
A (B and C)
(A and B) or C and D)
(A and B or C and D)`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions