re = /(\d+(\.\d+)?%)/
str = 'Bachelor of Engineering in Electronics from in 2013 with 60%.
Diploma (Electronics & Video Engineering) from in 2009 with 79.39%.
SSC from in 2006 with 61.71%.'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html