import Foundation
let pattern = #"(?<prefix1>\d{0,3}?)(?<suffix1>\d{1,3})\/(?<prefix2>\d{0,3}?)(?<suffix2>\d{1,3})\/"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
1/1/
12/1/
123/1/
1234/1/
12345/1/
123456/1/
1/12/
1/123/
1/1234/
1/12345/
1/123456/
12/12/
123/12/
1234/12/
12345/12/
123456/12/
12/123/
12/1234/
12/12345/
12/123456/
123/123/
1234/123/
12345/123/
123456/123/
123/1234/
123/12345/
123/123456/
1234/1234/
12345/1234/
123456/1234/
1234/12345/
1234/123456/
12345/12345/
123456/12345/
12345/123456/
123456/123456/
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression