re = /(?<=(['"])\b)(?:(?!\1|\\).|\\.)*(?=\1)/m
str = '"2005014523","34.95661","-96.74025","1","52","52","5/17/2020 - 11:10 AM","By 5/17/2020 2:38 PM","5/17/2020 - 12:50 PM","UNPLANNED"'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html