re = /^(?:\d{8}[A-Z]|\d{1,8})$/m
str = '# Correctos (incluyendo parciales)
1
12
123
1234
12345
123456
1234567
12345678
12345678Z
# Incorrectos
1Z
123456789
1/
/
@#~
12345678AZ
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html