re = /^(?!0)(?:9\d\d|\d{4,5}|[1-7]\d{5}|8[0-5]\d{4}|86[0-3]\d{3}|864000)$/m
str = '0
10
899
900
1000
1001
99999
799999
800000
859999
860000
863999
864000
864001
999999
1000000
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html