re = /[^\d](;)\n/
str = '15;WB;250;2013-12-16;275;2013-12-16;18573; 16,00;
JAN KOWALSKI;WARSZAWA 1/9 m.5;
16;WB;3;2014-01-03;305;2014-01-03; 20,00;
JAN KOWALSKI;WARSZAWA;
17;WB;9;2014-01-10;382;2014-01-10; 30,00;
JAN KOWALSKI;WARSZAWA, Ulica JELEÑSKA 21 m.10;'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html