re = /^\d{3}(?:(?:[ \.\-]?)\d{2}){3}$/m
str = '123456789
123 45 67 89
123.45.67.89
123-45-67-89
1234
1341234311341324'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html