const regex = /(?:\s|\\n\\n)*(?<subject>\S+(?:\s[IVX]+\.?)?)(?:\s|\\n\\n)+(?<teacher>\S+)(?:\s|\\n\\n)+(?<room>\S+)(?:\s|\\n\\n)*/g;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('(?:\\s|\\\\n\\\\n)*(?<subject>\\S+(?:\\s[IVX]+\\.?)?)(?:\\s|\\\\n\\\\n)+(?<teacher>\\S+)(?:\\s|\\\\n\\\\n)+(?<room>\\S+)(?:\\s|\\\\n\\\\n)*', 'g')
const str = `TSG MUM \\n\\nBS06-312
RQWE. FKB \\n\\nBS06-204
NM. JAK \\n\\nBS06-E05
DB. FKB \\n\\nBS06-312
IGT. resetk \\n\\nWender.
ENG I. \\n\\nWEHN BS06-E06 \\n\\nENG II \\n\\nFLEM BS06-203
ITSI. MUM \\n\\nBS06-E02
PQT. RIE \\n\\nBS11-QCR PQT \\n\\nMARK BS11-QCR \\n\\nPQT FIS \\n\\nBS11-QCR
INC FEY \\n\\nBS06-309
ABS. DOE \\n\\nBS06 ABS \\n\\nVOG BS06 \\n\\nABS HEI \\n\\nBS06 ABS \\n\\nMOR BS06 \\n\\nABS REM \\n\\nBS06 ABS \\n\\nDEI BS06 \\n\\nABS THA \\n\\nBS06
ENG III. \\n\\nGLIT BS06-209 \\n\\nENG II \\n\\nWANN BS06-208`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions