import Foundation
let pattern = #"(\(\s*(?P<Val>[a-zA-Z]+[0-9]*|[0-9]+|\'.*\'|\[.*\])\s*(ni|in|[*\/+-]|[=!><]=|[><])\s*((?&Val))\s*\))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
(a in b)
(a ni b)
(a in [1,2,3])
([1,2,3] == [1,2,3])
(a == 'Ahmad Hajjar')
((a+1)==b)
(1==1)
( a == a)
(1==2)
(x1!=y)
(xa1*3)
((7*3)==21)
((17*9)!=(a+b))
((( a + b )*(c-d))==(5/2))
( a+b)
( a - b)
( a/b )
( a * b )
(ahmad>feras)
(ahmad>=feras)
(feras<ahmad)
(feras<=ahmad)
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression