re = /(.*?)\n(.*?)/
str = '02.04.2024 02.04.2024 280 "ADDEBITO SEPA DD PER FATTURA A VOSTRO CARICO Incasso 2023-03-24
17 53 26.259 SDD da IT38ZZZ0000001168010070 KNOT SRL mandato nr.
BJWRS001212620072" -871,18
02.04.2024 29.03.2024 43 "PAGAMENTO VISA Contactless del 29/03/2024 CARTA *8642 DI EUR 15,12 2L
AOSTA" -15,12
03.04.2024 03.04.2024 48 "BONIFICO A VOSTRO FAVORE BONIFICO SEPA DA LA KIUVA SOCIETA
COOPERATIVA PER fattura COMM 0,00 SPESE 0,00 TRN 1001240942034482" 1.098,00'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html