import Foundation
let pattern = #"(.*?)\n(.*?)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
02.04.2024 02.04.2024 280 "ADDEBITO SEPA DD PER FATTURA A VOSTRO CARICO Incasso 2023-03-24
17 53 26.259 SDD da IT38ZZZ0000001168010070 KNOT SRL mandato nr.
BJWRS001212620072" -871,18
02.04.2024 29.03.2024 43 "PAGAMENTO VISA Contactless del 29/03/2024 CARTA *8642 DI EUR 15,12 2L
AOSTA" -15,12
03.04.2024 03.04.2024 48 "BONIFICO A VOSTRO FAVORE BONIFICO SEPA DA LA KIUVA SOCIETA
COOPERATIVA PER fattura COMM 0,00 SPESE 0,00 TRN 1001240942034482" 1.098,00
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
if let firstMatch = regex.firstMatch(in: testString, range: stringRange) {
let result: [String] = (1 ..< firstMatch.numberOfRanges).map { (testString as NSString).substring(with: firstMatch.range(at: $0)) }
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression