import Foundation
let pattern = #"\{(?>(?>(?(1)(?!))((?&GetNum))|(?(2)(?!))((?&GetNum))|(?(3)(?!))((?&GetNum))|(?(4)(?!))((?&GetNum))|(?(5)(?!))((?&GetNum))|(?(6)(?!))((?&GetNum))|(?(7)(?!))((?&GetNum))|(?(8)(?!))((?&GetNum))|(?(9)(?!))((?&GetNum))|(?(10)(?!))((?&GetNum)))(?:,(?!\})|(?=\}))){3,7}\}(?(DEFINE)(?<GetNum>(?!(?:\g{1}|\g{2}|\g{3}|\g{4}|\g{5}|\g{6}|\g{7}|\g{8}|\g{9}|\g{10})\b)\d+))"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
{331,2,989}
{1,2,3,4}
{1,2,1,4}
{1,2,3,4,6,9,10,}
{5,4,3,2,1}
{1,2,3,4,5,6,7,8,9,10}
{1,2,33,5,6,7,8,9,0,4}
{1,2,33,5,6,7,8,9,44}
{331,2,989}
{331,2,989}
{331,2,98,9}
{331,2,989}
{1,2,3,4}
{1,2,1,4}
{1,2,3,4,6,9,10}
{5,4,3,2,1}
{1,2,3,4,6,9,}
{1,2,3,4,7,8,2345102}
{1,2,3,4,5,6,7,8,9,0}
{1,2,3,4,5,6,7,8,9,10}
{1,2,3,4,5,6,7,8,22}
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression