re = /^(?(?=99)99(\.0+)?|([1-9]\d?(\.\d+)?))$/m
str = '1.00
99.00
0.00
1.25
56.9658
99
99.25
99.00
9.36
99.58
5
98.52
90'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html