re = /^1?\(\d{3}\)[-. ]?(\d{3})$/m
str = '1(123)123
(123)123
1(123) 123
2(123) 123
1(123)%123
1(123)12
1(12)123'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html