using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"(?:(?:^|\G(?<!^)[^'""]*"")[^""]*+(?:""[^""']*""[^""]*)*+""|\G(?<!^))[^'""]*+(')";
string input = @""" This is a random sentence ' with 'a quote, the quote should match""
"" There is no quote here thats the problem"" Anything here should not match but now it does: ' .
"" Some text "" some more text "" this is a quote : ' that should match""
"" When there is a quote (') here, the other one does not work : "" ' and that's perfect "" even if you remove the first one this : "" (') "" will make it work because of the greedy ( I think ) but ifyou remove those between parenthesis, the other one is matching as of now, which I do not want to happen.""
Another example would be this one : The following should not work, but it does ""This is being quoted"" not this: (') "" and this is also being quoted ""
""'""
";
foreach (Match m in Regex.Matches(input, pattern))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx