const regex = /trans\('([a-zA-Z]+[.])+(testword|testword2|testword1|testword3)'\)/g;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('trans\\(\'([a-zA-Z]+[.])+(testword|testword2|testword1|testword3)\'\\)', 'g')
const str = `Welcome to RegExr v2.1 by gskinner.com, proudly hosted by Media Temple!
Edit the Expression & Text to see matches. Roll over matches or the expression for details. Undo mistakes with ctrl-z. Save Favorites & Share expressions with friends or the Community. Explore your results with Tools. A full Reference & Help is available in the Library, or watch the video Tutorial.
Sample text for testing:
abcdefghijklmnopqrstuvwxyz ABCDEFGHIJKLMNOPQRSTUVWXYZ
0123456789 _+-.,!@#\$%^&*();\\/|<>"'
12345 -98.7 3.141 .6180 9,000 +42
555.123.4567 +1-(800)-555-2468
foo@demo.net bar.ba@test.co.uk
www.demo.com http://foo.co.uk/
http://regexr.com/foo.html?q=bar
https://mediatemple.net
trans('asd.asd.testword')
trans('asddd.asd.asd.testword1')
trans('asggfd.asd.asd.asd.asd.testword2')
trans('asdrtd.testword3')
((^|, )(part1|part2|part3))+\$`;
const subst = `trans('common.$2')`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions