re = /[a-z]+
# you mean like this?
#\ (?:\d{4,5}(?=\.\d{2}))
# only downside is you have to escape spaces/mx
str = 'now you can has other regeex parts unused 1234.12'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html