import Foundation
let pattern = #"(^((\*\/)?([1-5]?[0-9])((\,|\-|\/)\d+)*|\*)\s((\*\/)?((2[0-3]|1[0-9]|[0-9]))((\,|\-|\/)\d+)*|\*)\s((\*\/)?([1-9]|[12][0-9]|3[01])((\,|\-|\/)\d+)*|\*)\s((\*\/)?([1-9]|1[0-2])((\,|\-|\/)\d+)*|\*)\s((\*\/)?[0-6]((\,|\-|\/)\d+)*|\*)$)|@(annually|yearly|monthly|weekly|daily|hourly|reboot)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = ##"""
# should pass:
12 1 1 * 1
0 1 1 * 1,2
0 1 1 * 1,2,3
0 1 * * 1/4
0 */2 * * *
0 9-17 * * *
0 * * * 2/4
* * * * *
* * * * *
0 4 * * 1-5
*/5 * * * *
37 1-23/2 * * *
0 0,12 1 */2 *
0 0 1,15 * 3
@weekly
0 5,17 * * *
5 0 * 8 *
0 22 * * 1-5
23 0-20/2 * * *
0 0,12 1 */2 *
# should not pass:
0 * * 0 1-4
0 0 0 12 *
*-* * * * *
* * *-1 * *
*1 * 1 * *
1* * 1 * *
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression