re = /^(?:\d{7}[\da-zA-Z]\d{0,2}|\d{1,7})$/m
str = '1
123
1234567890
1234567a
1a
123456789a
12345678901'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html