re = /(\d)(?=((\d\d\d)+(\D|$)))/m
str = '12 мало
лучше 123
1234 почти
12354 хорошо
стало 123456
супер 1234567'
subst = '\\1.'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html