re = /\b(?!127|10|192\.168)(?:\d{1,3}\.){3}\d{1,3}(?:\/\d{1,2})?/m
str = '10.0.0.0
11.0.0.0
126.0.0.0
127.0.0.0
127.123.0.0
128.123.0.0
192.168.0.0
192.169.0.0'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html