import re
regex = re.compile(r"(\b\d\b)")
test_str = "8 5E 9C 52 30 0"
subst = "0\\1"
result = regex.sub(subst, test_str)
if result:
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html