import Foundation
let pattern = #"<(ol|ul)([^>]*?)(type="[^"]*")([^>]*?)>"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
<ol type="a"><li></span>Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut</span><ol><li></span>aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit</span><ul type="i"><li ></span>In voluptate velit esse type="a" cillum dolore eu fugiat nulla pariatur.<ol style="abc" type="a">ádasdasd
<ol style="abc">sadas</ol><ol style="abc" type="a" abc="ee">sadas</ol><ol type="a" abc="ee">sadas</ol>
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression